When octane (C8H18) is burned in oxygen carbon dioxide and water are produced. If 320 g of octane are burned and 32 g of water are recovered, what is the percent yield of the experiment? The equation is 2C8H18 + 25O2 --> 16CO2 + 18H2O.
Could anyone explain the steps of this to me? I feel like whenever we go over it in class I get it, but I just forget how to do the problems as soon as I get home, and the textbook still confuses me.
Could anyone explain the steps of this to me? I feel like whenever we go over it in class I get it, but I just forget how to do the problems as soon as I get home, and the textbook still confuses me.