T Tay New member Oct 2, 2009 #1 20 cm3 of 0.1mol dm-3 HCl requires exactly 40 cm3 of NaOH to neutrilise it. Calculate the concentration of NaOH. Could you show me how you work it out as well plz?
20 cm3 of 0.1mol dm-3 HCl requires exactly 40 cm3 of NaOH to neutrilise it. Calculate the concentration of NaOH. Could you show me how you work it out as well plz?
S skipper New member Oct 2, 2009 #2 molarity = moles / liters rearrange to solve for moles- moles = molarity x liters HCl + NaOH --> NaCl + H2O 1 mole HCl neutralized by 1 mole of NaOH M x L = M x L 0.1 M x 0.020 L = ? M x 0.040 L ? M = 0.1 x 0.02 / 0.04 = 0.05 M NaOH = 0.05 M
molarity = moles / liters rearrange to solve for moles- moles = molarity x liters HCl + NaOH --> NaCl + H2O 1 mole HCl neutralized by 1 mole of NaOH M x L = M x L 0.1 M x 0.020 L = ? M x 0.040 L ? M = 0.1 x 0.02 / 0.04 = 0.05 M NaOH = 0.05 M
