Chemistry- figuring out theoretical grams and percent yeild ?

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chemfailure

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Okay so I definitly do not know how to do this, I am prety sure I understand everthing else.
SOOOO
we have CuSO4 * 5H20
mass=1.959g
molar mass = 249.7 g/mol
moles = 0.0078
molar mass of Cu ??? maybe 79.545 ??
theoretical yeild in g of CuO >>>???
mass of filter paper 3.754
expiremental mass of CuO - 3.531
Percent yeild of CuO ?????
Percent deviation b/w eperimental anth theoretical yields ????
So all the ones anserwed I figured out, but I am at a loss for the question marked ones.... I have researched and I still cannot figure it out pleae help ?
oh and just in case you need to know this was an expirement and the balanced equation i did for aqueous copper (II) sulfate pentahydrate and sodium hydroxide is
CuSo4 *5H2O + 2NaOH----> [Cu(OH)2] + 2Na +SO4+5H2O

and for the decomposition of copper(II) hydroxide
1[Cu(oh)2] --(heat)-> 1CuO+H2O
and lastly overall balanced equation starting with copper(II) sulfate pentahydrate and ending with copper(II) oxide
CuSO4*5H2O+2NaOH-->2Na+So4+6H2O+CuO

dont kow if this is relevant or not but just in case
Thanks susie , but this is allt he info that was given to me, I dont know what the theoretical should be nor what the actual should be, I would love if someone could show steps, Im not just looking for answers I really do want to kow how to d this. I dont understand what your saying
 
It is not as hard as you think...


Theoretical yield is just that, the mass expected to be obtained..

Write out your equation and obtain your moles of CuO, which i am guessing you could do right?

molar ratios?

Your actual yield should have been given to you..

Now to obtain the percentage yield it is theoretical over actual yield, which will give you a percentage
 
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