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snpylvr913
Guest
A method requires 740 mL of a 5% (w/v) solution of tri sodium citrate. The only citrate you have available is the dihydrate, C6H5O7Na3.2H2O with a formula weight of 294.1 How much would you have to weigh out to make up this solution?
(w/v) = g/100 mL
(w/v) = g/100 mL