SkinsAddict
New member
Imagine that you are in chemistry lab and need to make 1.00 L of a solution with a pH of 2.70.
You have in front of you
100 mL of 6.00×10−2 M HCl ,
100 mL of 5.00×10−2 M NaOH , and
plenty of distilled water.
You start to add HCl to a beaker of water when someone asks you a question. When you return to your dilution, you accidentally grab the wrong cylinder and add some . Once you realize your error, you assess the situation. You have 80.0 mL of and 90.0 mL of left in their original containers.
Assuming the final solution will be diluted to 1.00 L , how much more HCl should you add to achieve the desired pH?
Thanks a lot!
You have in front of you
100 mL of 6.00×10−2 M HCl ,
100 mL of 5.00×10−2 M NaOH , and
plenty of distilled water.
You start to add HCl to a beaker of water when someone asks you a question. When you return to your dilution, you accidentally grab the wrong cylinder and add some . Once you realize your error, you assess the situation. You have 80.0 mL of and 90.0 mL of left in their original containers.
Assuming the final solution will be diluted to 1.00 L , how much more HCl should you add to achieve the desired pH?
Thanks a lot!