holy_warrior
New member
Solve the vector differential equation x' = Ax if A = 6 -8
2 2
After solving for eigenvalues and eigenvectors, i got one of them v = r(2, 1). However the eigenvalues is (h - 2)^2 which lead to x1(t) = e^2t(v1 + tv0)
I'm wondering why they put simplicity, they put v1 = [1, 0]?
2 2
After solving for eigenvalues and eigenvectors, i got one of them v = r(2, 1). However the eigenvalues is (h - 2)^2 which lead to x1(t) = e^2t(v1 + tv0)
I'm wondering why they put simplicity, they put v1 = [1, 0]?