M MÃ quei Guest Aug 17, 2009 #2 I'll first find the inverse of f f(x) = (1-x)/(x-3) f(x)*(x-3) = 1-x xf(x) + x = 1 + 3f(x) x = (1+3f(x))/(f(x)+1) g(f(x)) = 2/x-1 = 2/[(1+3f(x))/(f(x)+1)]-1 Now just do the math and then substitute f(x) by x in the end (or any other time, really)
I'll first find the inverse of f f(x) = (1-x)/(x-3) f(x)*(x-3) = 1-x xf(x) + x = 1 + 3f(x) x = (1+3f(x))/(f(x)+1) g(f(x)) = 2/x-1 = 2/[(1+3f(x))/(f(x)+1)]-1 Now just do the math and then substitute f(x) by x in the end (or any other time, really)
