calculating heat release, please help, even a formulae would do!!?

  • Thread starter Thread starter sammi
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sammi

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The value of delta H for the reaction below is -126kJ

2Na2O2(s) + 2H2O(l) >> 4NaOH(s) + O2(g)

The amount of heat that is released by the reaction of 25,0 g of Na2O2 with H2O is _________kJ

a) 20.2
b)40.4
c)67.5
d)80.8
e)-126
 
number of mole of Na2O2 = 25 / (23x2 + 16x2) = 0.32mol
heat released = 0.32/2 x 126 = 20.16 kJ
Ans = A
 
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