Calculating E from coulombs law?

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jeir35

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In the picture below, three very large sheets are separated by equal distances of 19 cm. The first and third sheets are very thin and nonconducting and have surface charge densities of 2 mC/m2 and -2 mC/m2 respectively. The middle sheet is conducting but has no net charge.


(a)What is the electric field E0 inside the middle sheet?
0

(b)What is the charge density s on the surface of the middle sheet facing the left sheet?
-2

(c)What is the charge density s on the surface of the middle sheet facing the right sheet?
2

(d)What is the magnitude of the electric field E1 between the left and middle sheets?

this is where i am stuck, i know E= surface density/ 2eo

im just confused my answers arent working

i thought it would be 2( .002 C/N / 2 * 8.85e-12) but that doesnt work.
 
If the sheet is non-conducting, the field from a surface charge density of ? is ?/(2*?0). Why do you have another factor of 2 in your final answer? It should be (2*10^-3)/(2*8.85*10^-12) N/C. With the conducting sheet between the outer planes, the planes are isolated from each other with respect to charge-generated fields. Field lines from the right sheet cannot penetrate the conductor.
 
If the sheet is non-conducting, the field from a surface charge density of ? is ?/(2*?0). Why do you have another factor of 2 in your final answer? It should be (2*10^-3)/(2*8.85*10^-12) N/C. With the conducting sheet between the outer planes, the planes are isolated from each other with respect to charge-generated fields. Field lines from the right sheet cannot penetrate the conductor.
 
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