Question 1 (1 point)
Polaris, the North Star, does not appear to move in the sky because:
a.The stars are fixed relative to each other
b.It lies approximately over the rotational axis of the Earth
c.It is too nearby for its motion to be discernible
d.It is located directly overhead for everyone on Earth
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Question 2 (1 point)
for the next two questions - the celestial grids that can be found in the course contents under "Starry Night Annotated Planetarium Shows" will be very useful.
As seen from Thunder Bay, what is the azimuth of the rising point of a star having declination -30 degrees
a.azimuth 44 degrees
b.azimuth 136 degrees
c.azimuth 226 degrees
d.azimuth 324 degrees
e.Such a star would be always below the horizon when viewed from Thunder Bay
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Question 3 (1 point)
Which of the following could be the equatorial co-ordinates of a star that rises to the South of East when viewed from Thunder Bay
a.Declination 60 degrees, Right Ascension 13 hours
b.Declination 30 degrees, Right Ascension 6 hours
c.Declination -30 degrees, Right Ascension 1 hours
d.Declination -60 degrees, Right Ascension 20 hours
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Question 4 (1 point)
Betelguese has celestial co-ordinates with Right Ascension approximately 6 hours and Declination approximately 0 degrees. What is the sidereal time when Betelguese sets ?
a.0 hours
b.6 hours
c.12 hours
d.18 hours
e.not enough information is given to determine the hour angle
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Question 5 (1 point)
Which of the following groups of information are sufficient to determine the local celestial co-ordinates of a star
a.Right Ascension and hour angle
b.Right Ascension and Time of day
c.Right Ascension and Date
d.Declination and hour angle
e.Declination and Date
Those are my questions lol I dont get it and need to get by this part of the course. These 5 questions will get me by. The declination of Thunder Bay is ~50 that is what you may need to help with these questions. Thanks
Polaris, the North Star, does not appear to move in the sky because:
a.The stars are fixed relative to each other
b.It lies approximately over the rotational axis of the Earth
c.It is too nearby for its motion to be discernible
d.It is located directly overhead for everyone on Earth
Save answer
Question 2 (1 point)
for the next two questions - the celestial grids that can be found in the course contents under "Starry Night Annotated Planetarium Shows" will be very useful.
As seen from Thunder Bay, what is the azimuth of the rising point of a star having declination -30 degrees
a.azimuth 44 degrees
b.azimuth 136 degrees
c.azimuth 226 degrees
d.azimuth 324 degrees
e.Such a star would be always below the horizon when viewed from Thunder Bay
Save answer
Question 3 (1 point)
Which of the following could be the equatorial co-ordinates of a star that rises to the South of East when viewed from Thunder Bay
a.Declination 60 degrees, Right Ascension 13 hours
b.Declination 30 degrees, Right Ascension 6 hours
c.Declination -30 degrees, Right Ascension 1 hours
d.Declination -60 degrees, Right Ascension 20 hours
Save answer
Question 4 (1 point)
Betelguese has celestial co-ordinates with Right Ascension approximately 6 hours and Declination approximately 0 degrees. What is the sidereal time when Betelguese sets ?
a.0 hours
b.6 hours
c.12 hours
d.18 hours
e.not enough information is given to determine the hour angle
Save answer
Question 5 (1 point)
Which of the following groups of information are sufficient to determine the local celestial co-ordinates of a star
a.Right Ascension and hour angle
b.Right Ascension and Time of day
c.Right Ascension and Date
d.Declination and hour angle
e.Declination and Date
Those are my questions lol I dont get it and need to get by this part of the course. These 5 questions will get me by. The declination of Thunder Bay is ~50 that is what you may need to help with these questions. Thanks