Given the following information, what is the final temperature when the Al is added to the water under the following conditions in a calorimeter?
30.0 g H2O
2.5 g Al
Ti(H2O) = 20.0°C
Ti(Al) = 62.0°C
cp(H2O) = 75.3 J/(mol•°C)
cp(Al) = 24.35J/(mol•°C)
a. 23.8 J/(mol•°C)
b. 21.5°C
c. 22.2°C
d. -21.5°C
When I tried it, I kept getting a value that is a little less than 20.7 degrees, which cannot be right, because it is not even an answer choice.
30.0 g H2O
2.5 g Al
Ti(H2O) = 20.0°C
Ti(Al) = 62.0°C
cp(H2O) = 75.3 J/(mol•°C)
cp(Al) = 24.35J/(mol•°C)
a. 23.8 J/(mol•°C)
b. 21.5°C
c. 22.2°C
d. -21.5°C
When I tried it, I kept getting a value that is a little less than 20.7 degrees, which cannot be right, because it is not even an answer choice.