S
Shoua K
Guest
Just note that I'm not taking the class itself at the moment.
I'm trying to find how much heat is released when 250 g of Octane (c8h18) is burned:
c8h18 (liquid) + (25/2) o2 (gas)--> 8 co2 (gas) + 9 h2o (liquid)
∆H° = -5450 kJ
(lowercase letters are the elements)
I know that this is an exothermic reaction and somehow involves using the enthalpy change formula [∆H° = ∆H = H(products) - H(reactants)].
I also know that
Energy released by the reaction = specific heat capacity ○ mass of solution ○ increase in temperature
So,
Energy released = specific heat capacity ○ 250 g ○ ∆T .
What I don't know is if I'm even using the right formula to find the heat released, and if so, what the specific heat capacity is and how to find ∆T.
Thanks.
-- Sorry, this is Thermochemistry.
I'm trying to find how much heat is released when 250 g of Octane (c8h18) is burned:
c8h18 (liquid) + (25/2) o2 (gas)--> 8 co2 (gas) + 9 h2o (liquid)
∆H° = -5450 kJ
(lowercase letters are the elements)
I know that this is an exothermic reaction and somehow involves using the enthalpy change formula [∆H° = ∆H = H(products) - H(reactants)].
I also know that
Energy released by the reaction = specific heat capacity ○ mass of solution ○ increase in temperature
So,
Energy released = specific heat capacity ○ 250 g ○ ∆T .
What I don't know is if I'm even using the right formula to find the heat released, and if so, what the specific heat capacity is and how to find ∆T.
Thanks.
-- Sorry, this is Thermochemistry.