L LoNe WoLf Guest Oct 12, 2008 #1 ...battery. How many milliliters of ? 1.4 M NaHCO3 must be poured on the spill to react completely with the sulfuric acid?
...battery. How many milliliters of ? 1.4 M NaHCO3 must be poured on the spill to react completely with the sulfuric acid?
S Steve O Guest Oct 12, 2008 #2 if they reacted 1:1 .... M1V1 = M2V2 (2.7M)(91ml) = (1.4M)(V2) V2 = 175.5 ml of NaHCO3 would be needed but the react: 1 mole H2SO4 & 2 moles NaHCO3--> so it will take twice as much NaHCO3 your answer is 351 ml
if they reacted 1:1 .... M1V1 = M2V2 (2.7M)(91ml) = (1.4M)(V2) V2 = 175.5 ml of NaHCO3 would be needed but the react: 1 mole H2SO4 & 2 moles NaHCO3--> so it will take twice as much NaHCO3 your answer is 351 ml
S Steve O Guest Oct 12, 2008 #3 if they reacted 1:1 .... M1V1 = M2V2 (2.7M)(91ml) = (1.4M)(V2) V2 = 175.5 ml of NaHCO3 would be needed but the react: 1 mole H2SO4 & 2 moles NaHCO3--> so it will take twice as much NaHCO3 your answer is 351 ml
if they reacted 1:1 .... M1V1 = M2V2 (2.7M)(91ml) = (1.4M)(V2) V2 = 175.5 ml of NaHCO3 would be needed but the react: 1 mole H2SO4 & 2 moles NaHCO3--> so it will take twice as much NaHCO3 your answer is 351 ml
