When two resistors, s and t, are connected in parallel, their resistance combined is equal to
1/R = 1/s + 1/t
If s is increased by 1, and t is reduced by 1, what is the change in R?
This is a question from my math textbook that I've been unable to solve all night. I have the answer in the back of my book, but I have no idea how to get it. If you answer, please show your work or explain what I have to do, I'm really stuck. Thanks in advance
1/R = 1/s + 1/t
If s is increased by 1, and t is reduced by 1, what is the change in R?
This is a question from my math textbook that I've been unable to solve all night. I have the answer in the back of my book, but I have no idea how to get it. If you answer, please show your work or explain what I have to do, I'm really stuck. Thanks in advance