A simple physics question...?

Kelso

New member
a)20 / 100 = 1 / 5 efficiency
If you need a percentage muliply by 100, so it's 20% efficient

b) energy wasted = total energy - energy used
i.e. enegery wasted = 100 - 20 = 80J
 
a)20 / 100 = 1 / 5 efficiency
If you need a percentage muliply by 100, so it's 20% efficient

b) energy wasted = total energy - energy used
i.e. enegery wasted = 100 - 20 = 80J
 
a light bulb radiates 20J of energy for every 100J of electrical energy supplied to it.
Calculate:
a) The efficiency of the light bulb.-
b)The energy wasted by the light bulb for every 100J of electrical energy supplied to it.
Thank you x
 
a)20 / 100 = 1 / 5 efficiency
If you need a percentage muliply by 100, so it's 20% efficient

b) energy wasted = total energy - energy used
i.e. enegery wasted = 100 - 20 = 80J
 
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