S
schmitterling
Guest
...parked car approximately...? ...7 feet. The moving car's weight is 2600, the parked car is 3500. The angle of the hit was approximately perpendicular. The back end of the parked car was moved approximately 26 degrees (the length of the parked car is 15.5, and the angle was calculated using an isosceles triangle...). Ok... given that the mass of the moving vehicle was 2600, the mass of the parked car was 3500, the back end of the parked car was moved about 7 feet (an angle of 26 degrees... the front end was stopped by a curb...but did move several inches, so basically the car pivoted...). I need to figure out how fast the moving car was going...and haven't come across the right formula in my book or online yet and would appreciate any help! ...if I left any information out that is needed please let me know. Thanks!