A math riddle. Logic and guessing is slighty needed or watever. Ezy 13 points.?

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OiNeedAnAnswer

New member
2 points for answering, I will give one thumbs up, and I will give the best answer :)

Ok.
A Russian woman who lived in the 18th century....
She alsways had either twins, trips, or quadrups.
The # of sets of two types were both square numbers.
One type was a one-digit prime #.
The total amount of children was a two-digit # that was the X of two prime numbers.
The # of children who were quadruplets was greater than the number of sets of tiplets by a square number.
she had an odd # of children.
The number of sets (twins) - set (quads) is 0, or whole number but not a counting number.
# of twins minus # of trips is a palindrome.
To Brian,
That doesn't work,
the quadruplets minus triplets is square number. 4 - 7 is not a square number.
PPS. I already know that info about 69 children. The riddle changed all the numbers about the twins and trips and quads.
 
The logic is kind of skewed for this problem because you end up having to use a ton of variables. I had to try and solve this riddle a year ago at a math team competition. It really does involve a ton of guessing but I'll save you the effort. ;)

Feodor Vassilyev had 16 sets of twins, 7 sets of triplets, and 4 sets of quadruplets

The sets of twins(16) and quadruplets(4) are squares.
The set of triplets(7) is prime
The total amount of children, 96, is the product of primes (23x3)
The # of children who were quadruplets(16) was greater than the # of sets of triplets(7) by a square(9)
She had an odd number of children(69)
The # of sets of twins(7) - the # of sets of quads(4) is a whole number(3)
# of twins(32) - # of triplets(21) = a palindrome(11)

It all fits! In your additional details, you took the set # of quads instead of the total #.

~♫♪♫
 
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