B baby_fat1236 Guest Mar 16, 2010 #1 (with the wind) took 3 1/3 hours.? help Then find what was the speed of the wind in the question above?
(with the wind) took 3 1/3 hours.? help Then find what was the speed of the wind in the question above?
R ranjankar New member Mar 16, 2010 #2 Distance = 1920 Time = 6 Speed = 320km/hour Return Distance = 1920 Time = 3 1/3 hours Speed = 1920/ 3 1/3 = 1920 x 3/10 = 576km/ hour Let the actual speed of jet be a and wind be b a - b = 320 a + b = 576 Add 2a = 896 a = 448 448 - b = 320 b = 448- 320 = 128km/hour
Distance = 1920 Time = 6 Speed = 320km/hour Return Distance = 1920 Time = 3 1/3 hours Speed = 1920/ 3 1/3 = 1920 x 3/10 = 576km/ hour Let the actual speed of jet be a and wind be b a - b = 320 a + b = 576 Add 2a = 896 a = 448 448 - b = 320 b = 448- 320 = 128km/hour
