C Cricket c Guest Apr 30, 2009 #1 What is the centripetal acceleration of a point on the edge of the wheel?
P pinaibebeboo New member Apr 30, 2009 #2 centripetal acceleration (ac) = v^2/r T = 2(pi)r/V t = 1.4167rps, since you gave us 85rpm, but t has units of rounds per SECOND, not minute, so make sure to convert. then basic plug-n-chug gives you 11.8m/s^2
centripetal acceleration (ac) = v^2/r T = 2(pi)r/V t = 1.4167rps, since you gave us 85rpm, but t has units of rounds per SECOND, not minute, so make sure to convert. then basic plug-n-chug gives you 11.8m/s^2
P pinaibebeboo New member Apr 30, 2009 #3 centripetal acceleration (ac) = v^2/r T = 2(pi)r/V t = 1.4167rps, since you gave us 85rpm, but t has units of rounds per SECOND, not minute, so make sure to convert. then basic plug-n-chug gives you 11.8m/s^2
centripetal acceleration (ac) = v^2/r T = 2(pi)r/V t = 1.4167rps, since you gave us 85rpm, but t has units of rounds per SECOND, not minute, so make sure to convert. then basic plug-n-chug gives you 11.8m/s^2
