angle that the cannon can launch? Now imagine that you have a cannon that launches a ball. The angle that the cannon can
launch the ball at with respect to the horizontal is fixed because the cannon has rusted into a
permanant position.This fixed angle is "a" . Now imagine you are on a building roof at a height "H"
and there is a basketball hoop a distance "D" away from the base of the building. The basketball
hoop is a distance "h" from the ground. You point the cannon in the direction of the hoop and
want to shoot the ball into the hoop. You can adjust the speed with which the ball leaves the
cannon by altering the amount of gun powder used in the blast. With what speed must the ball
leave the cannon in order to have a good chance of going through the hoop. Call
this optimum speed " V* ".
launch the ball at with respect to the horizontal is fixed because the cannon has rusted into a
permanant position.This fixed angle is "a" . Now imagine you are on a building roof at a height "H"
and there is a basketball hoop a distance "D" away from the base of the building. The basketball
hoop is a distance "h" from the ground. You point the cannon in the direction of the hoop and
want to shoot the ball into the hoop. You can adjust the speed with which the ball leaves the
cannon by altering the amount of gun powder used in the blast. With what speed must the ball
leave the cannon in order to have a good chance of going through the hoop. Call
this optimum speed " V* ".