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to answer such question it is important to know the balance equation so that u can find out the ratio N2O5----> 2NO2 + 1/2O2 1) N2O5:NO2 1:2 X:4 so X=2 volumes 2) N2O5:O2 1:1/2 X:3 so X=6 volumes C4H10+ 13/2O2---->4CO2 + 5H2O 1) C4H10:CO2 1:4 10:X X=40cm3 the 2dm3 u mention izit 2dm^3? if so...

in butane it consist of all cis-but-2-ene,trans-but-2-ene,but-1-ene and the other type isomer or contain only one type?for example only contain but-1-ene?? this seem like a stupid question but i really confused here i asking the wrong question it should be... in BUTENE it consist of all...

if there is one chiral carbon how many isomer are there?? i think is 2..enantiomers(the original image and mirror image) but how come the answer will be 4 isomer?? someone one know why??

From the following data... C (graphite) +O2 ---> CO2 -393.5 H2 + 1/2O2 ---> H2O -285.8 2C2H6 + 7O2 ---> 4CO2 + 6H20 -3119.6 2C (graphite) +2O2 ---> 2CO2 -393.5X2 3H2 + 3/2O2 ---> 3H2O -285.8X3 2CO2 + 3H20 ---> C2H6 + 7/2O2 -3119.6 reverse and divide by 2=+3119.6/2...

none... each orbital can only occupy by maximum 2 electron which are opposite spin only