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Can someone help me with this please? I've done it, but I'm not sure whether the answer is right. The question is Given A is reflex and cos A = 1/5, find sin2A. This is my working.. sin A = -sqrt24 / 5 sin2A= 2sinAcosA = 2 x (-sqrt24 / 5) x (1/5) = -2 sqrt24 / 25 Can...