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  1. T

    Find the singular points of this differential equation and classify them as

    as typed 2 is regular but 0 is irregular as lim { x---> 0 } [ x(5x-7) / x²] does not exist...that is 0 is a pole of order 2 for p_1 (x) =(5x-7) / (x² [x-2]) and 2 is a pole of order 1
  2. T

    Find the singular points of this differential equation and classify them as

    as typed 2 is regular but 0 is irregular as lim { x---> 0 } [ x(5x-7) / x²] does not exist...that is 0 is a pole of order 2 for p_1 (x) =(5x-7) / (x² [x-2]) and 2 is a pole of order 1
  3. T

    Find the singular points of this differential equation and classify them as

    as typed 2 is regular but 0 is irregular as lim { x---> 0 } [ x(5x-7) / x²] does not exist...that is 0 is a pole of order 2 for p_1 (x) =(5x-7) / (x² [x-2]) and 2 is a pole of order 1
  4. T

    Find the singular points of this differential equation and classify them as

    as typed 2 is regular but 0 is irregular as lim { x---> 0 } [ x(5x-7) / x²] does not exist...that is 0 is a pole of order 2 for p_1 (x) =(5x-7) / (x² [x-2]) and 2 is a pole of order 1
  5. T

    Find the singular points of this differential equation and classify them as

    as typed 2 is regular but 0 is irregular as lim { x---> 0 } [ x(5x-7) / x²] does not exist...that is 0 is a pole of order 2 for p_1 (x) =(5x-7) / (x² [x-2]) and 2 is a pole of order 1
  6. T

    Find the singular points of this differential equation and classify them as

    as typed 2 is regular but 0 is irregular as lim { x---> 0 } [ x(5x-7) / x²] does not exist...that is 0 is a pole of order 2 for p_1 (x) =(5x-7) / (x² [x-2]) and 2 is a pole of order 1
  7. T

    Find the singular points of this differential equation and classify them as

    as typed 2 is regular but 0 is irregular as lim { x---> 0 } [ x(5x-7) / x²] does not exist...that is 0 is a pole of order 2 for p_1 (x) =(5x-7) / (x² [x-2]) and 2 is a pole of order 1
  8. T

    Why do solutions to ODE need linear independence?

    since the solutions will be of the form c1 g(x) + c2 w(x) where both g(x) and w(x) solve the ODE if w(x) = c3 g(x) then you really only have [c1 + c3] g(x) = C4 g(x)...one solution
  9. T

    Why do solutions to ODE need linear independence?

    since the solutions will be of the form c1 g(x) + c2 w(x) where both g(x) and w(x) solve the ODE if w(x) = c3 g(x) then you really only have [c1 + c3] g(x) = C4 g(x)...one solution
  10. T

    Why do solutions to ODE need linear independence?

    since the solutions will be of the form c1 g(x) + c2 w(x) where both g(x) and w(x) solve the ODE if w(x) = c3 g(x) then you really only have [c1 + c3] g(x) = C4 g(x)...one solution
  11. T

    Why do solutions to ODE need linear independence?

    since the solutions will be of the form c1 g(x) + c2 w(x) where both g(x) and w(x) solve the ODE if w(x) = c3 g(x) then you really only have [c1 + c3] g(x) = C4 g(x)...one solution
  12. T

    Why do solutions to ODE need linear independence?

    since the solutions will be of the form c1 g(x) + c2 w(x) where both g(x) and w(x) solve the ODE if w(x) = c3 g(x) then you really only have [c1 + c3] g(x) = C4 g(x)...one solution
  13. T

    Please Help with CALC test question...? Tricky!!!?

    f ' (g(2)) g '(2)...you compute
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