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One of my friends in another country has Ti-87 calculator. She can find the button for ln but not for log (to base 10). For now I have told her to calculate logX by lnX/ln10 but is there any single button to calculate log to base 10 directly? Let me know where that button is or if there is any...

It is not that great. Means if your in a traffic or any rushy areas there is a chance you could miss the call. for details just go to this link below. http://tinyurl.com/yj9ka4f This'll clear your doubt about any gsm phone there is!

No there is no default location toset for bluetooth in your device. The files if small in size it will occupy the phone memory if there is any free space available. if not it directly rooted to your memory card directly as a dump.

overall n900 is the best best in comparision in performance vise! but availability of the applications is low at this point. But S60 v5 software of N97 is being elder by an year it has some advantages in applications sector the camera quality is same for the both devices and in music N97 is...

It is actually it is difficult to choose upgrade for N95! As you know the potential of the device N95 it is always a challenge? There are four options: N97 - The goodness of Symbian with the touchscreen sweetness. big screen and widgets are also very good welcome to this device. N97 mini: -...

It is actually it is difficult to choose upgrade for N95! As you know the potential of the device N95 it is always a challenge? There are four options: N97 - The goodness of Symbian with the touchscreen sweetness. big screen and widgets are also very good welcome to this device. N97 mini: -...

Let Fn = normal force When the sled is moving on level ground then Fn = mg (on level ground)------(1) The crest of a hill is rounded. Therefore the child experiences downward centripetal acceleration. Let centripetal acceleration = a The two forces acting on the child are 1. Weight mg downward...

1) v^2 = vo^2 - 2gh vo^2 = v^2 + 2gh vo = sqrt(v^2 + 2gh) = sqrt(6.8^2 + 2 * 9.8 * 32) = 26 m/s Ans: 26 m/s 2) S = 5.7 cm t = 14 ms = 14 * 10^-3 s vo = 0 S = vo t + 1/2 a t^2 5.7 = 0 + 1/2 a (14 * 10^-3)^2 5.7 = 98 * 10^-6 a a = 5.7 / (98 * 10^-6) a = 5.82 * 10^4 cm/s^2 1 cm = 10^-2 m = 10^-2...

Velocity is constant. Therefore net force = 0 Therefore resistive force = forward thrust = 7.30E+5 N Ans: 7.30E+5 N _______________.

Velocity is constant. Therefore net force = 0 Therefore resistive force = forward thrust = 7.30E+5 N Ans: 7.30E+5 N _______________.

Velocity is constant. Therefore net force = 0 Therefore resistive force = forward thrust = 7.30E+5 N Ans: 7.30E+5 N _______________.

Velocity is constant. Therefore net force = 0 Therefore resistive force = forward thrust = 7.30E+5 N Ans: 7.30E+5 N _______________.

You will also need mass of a C-12 nucleus and the mass of a U-235 nucleus.

Yes you are right. From wavelength lambda calculate momentum (p) using p = h/lambda Now you know momentum (p) and mass(m=9.1 x 10^-31 kg) of an electron. So you can calculate the kinetic energy. Note: 10^-10 m is the diameter of an atom. So the calculations will give you KE of an electron...

Displacement S = 60 m Initial velocity vi = 100 km/h = 100 * 1000/3600 m/s = 250/9 m/s Final velocity vf = 0 a) Let acceleration = a vf^2 = vi^2 + 2aS 0 = (250/9)^2 + 2(a)(60) 0 = 771.6 + 120 a a = -771.6/120 = -6.43 m/s^2 Magnitude of acceleration = 6.43 m/s^2 b) a/g = 6.43/9.80 = 0.66 Ans...

In vertically downward direction:- Initial velocity = 0 (because the ball is moving horizontally) Acceleration = g = 9.8 m/s^2 Displacement h = 100 m h = 0 * t + 1/2 * gt^2 h = 1/2 * gt^2 t = sqrt(2h/g) = sqrt(2 * 100/9.8) = 4.52 s In horizontal direction:- Displacement d = 65 m Velocity = d/t...

Take the direction in which the 5 kg fish is initially moving as positive. Initially:- Mass of the larger fish M1 = 5 kg Velocity of the larger fish u1 = 1 m/s Mass of the smaller fish M2 = 1 kg Velocity of the smaller fish u2 = -4 m/s Finally, let the common speed of the two fish = v By...

The locomotives approach each other. Therefore relative speed = v + v = 2v = 2 * 80 = 160 km/h Distance = 7.0 km Time = distance/relative speed = 7.0/160 hr = 0.04375 hr = 0.04375 * 60 minute = 2.625 min Ans: 2.625 min (can round off to 2.6 min)

Initial speed u = 17 m/s 1. u^2/(2g) = 17^2/(2 * 9.8) = 289/19.6 = 14.7 m 2.) 2u/g = 2 * 17/9.8 = 3.47 second Note: After time u/g, it reaches to maximum height. It takes u/g to fall from maximum height to the point of throw. Therefore, in total it is in the air for 2u/g time.

All the three are polar.