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I think it is fairly simple but I don't understand how the teacher got to this answer: L= 0,5m D = 0,2m Phi,out = Integral v(z) * pi *D*dz = pi*D integral (v/2L) * z *dz = (pi*D*v)/(2L) [1/2 z²] = ((pi*D*v)/(4))*L the question is about a tube which is porous, which has lengt L and diameter D...