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the formula is h(t)=-4.9t^2+vt+h where h(t)=height t=seconds v=velocity h=initial height the question says one half second after springing from a high diving board, a diver reaches her highest point above water, 4.225m. if the diving board is 3m above water, how long is the diver in the air...

help pleaseeee im going into precal and i cannot figure out the answer to these questions! formula h(t)=-4.9t^2+vt+h where h(t) = height t= seconds v= velocity h= initial height im only given two variables ! a stone is thrown with anupward velocity of 14m/s from a cliff 30 m high a: find its...