Use the standard entalphy change of formation of the following compounds (given in kJmol-1) to calculate the entalpy of the reaction below:
?Hf C2H4: +52
?Hf H20: -242
?Hf C2H5OH: -46
C2H4 + H20 --> C2H5OH
So I do the cycle and end up doing the sum -(52-242)-46 =...
