68ft of a perennial border forms the hypotenuse of the triangle, and one leg is 28ft longer than the other legs. Find the length of the legs.
I set it up like this c^2=a^2+b^2
68^2=a^2+(x+28)^2
4624=2x^2+56x+784
0=2^2+56x-3840
0=(x-32)(x+60)
x=32
x=-60
what did I do wrong?
