Hi,
1. 2^(5/2) - 2^(3/2)
= √(2^5) - √(2^3)
= √{(2^4)•2} - √{(2^2)•2}
= 2²•√2 - 2•√2
= 4•√2 - 2•√2
= 2•√2
2.(1/x) = (1/a) = (1/b), where a â‰* b
x = a = b, where a â‰* b
so x = { } or NULL
3. 3•x² - 2•x + 7 = 0 ... divided by 3
.... x² -...