Given the following data,
H2(g) + 1/2 O2(g) => H2O(g) DGo = -236.0
2 H(g) + O(g) => H2O(g) DGo = -920.8
2 H(g) + 2 O(g) => H2O2(g) DGo = -1,068.0
2 O(g) => O2(g) DGo = -496.6
H2O2(l) => H2O2(g) DGo = 43.1
Determine DGfo for H2O2(l)
Correct : -178.0
Please show steps coz i want to learn...