Search results

At 25 degrees Celsius, the standard enthalpy of formation of HF(aq) is -320.0 kJ/mol. Of OH-(aq), it is -229.5 kJ/mol. Of F-(aq) it is -329.6 kJ/mol, and of H2O(l) it is -286.0 kJ/mol. Calculate the standard enthalpy of neutralization of HF(aq): HF(aq) + OH(aq) --> F-(aq) + H2O(l)