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Find the equation of the normal to the curve; 2x^3 - x(^2)y + y^3 = 1 at the point (2, -3) So I used implicit differentiation to get the gradient of the tangent. 2x^3 - x(^2)y + y^3 = 1 dy/dx = (2xy - 6x^2) / (3y^2 - x^2) at (2,-3) = -36 / 23 = Gradient = m Now I use y - y1 = m(x -x1) to...

A Helium-neon laser (? = 632.8 nm) is used to calibrate a diffraction grating. If the first-order maximum occurs at 20.5 Degrees, what is the line spacing? Note that ? = lambda