Recent content by youngandinsane

So, during my last visit to my doctor's office, my doctor told me that I could take my birth control straight through 2 month's worth before taking the sugar pills. It's a monophase pill. I'm about half way through my second 7 week cycle, but I'm just starting to get very anxious about how it...

horizontal asymptote is anywhere where the slope=0 slope=rise over run so rise (or the y value) has to be equal to 0 0=(6x+24)(3x-1)/(8-x)(2x+2) and you just do all the algebra from there

horizontal asymptote is anywhere where the slope=0 slope=rise over run so rise (or the y value) has to be equal to 0 0=(6x+24)(3x-1)/(8-x)(2x+2) and you just do all the algebra from there

horizontal asymptote is anywhere where the slope=0 slope=rise over run so rise (or the y value) has to be equal to 0 0=(6x+24)(3x-1)/(8-x)(2x+2) and you just do all the algebra from there

horizontal asymptote is anywhere where the slope=0 slope=rise over run so rise (or the y value) has to be equal to 0 0=(6x+24)(3x-1)/(8-x)(2x+2) and you just do all the algebra from there

horizontal asymptote is anywhere where the slope=0 slope=rise over run so rise (or the y value) has to be equal to 0 0=(6x+24)(3x-1)/(8-x)(2x+2) and you just do all the algebra from there

horizontal asymptote is anywhere where the slope=0 slope=rise over run so rise (or the y value) has to be equal to 0 0=(6x+24)(3x-1)/(8-x)(2x+2) and you just do all the algebra from there

horizontal asymptote is anywhere where the slope=0 slope=rise over run so rise (or the y value) has to be equal to 0 0=(6x+24)(3x-1)/(8-x)(2x+2) and you just do all the algebra from there

horizontal asymptote is anywhere where the slope=0 slope=rise over run so rise (or the y value) has to be equal to 0 0=(6x+24)(3x-1)/(8-x)(2x+2) and you just do all the algebra from there

horizontal asymptote is anywhere where the slope=0 slope=rise over run so rise (or the y value) has to be equal to 0 0=(6x+24)(3x-1)/(8-x)(2x+2) and you just do all the algebra from there

horizontal asymptote is anywhere where the slope=0 slope=rise over run so rise (or the y value) has to be equal to 0 0=(6x+24)(3x-1)/(8-x)(2x+2) and you just do all the algebra from there