Recent content by youknowwhatitis

so for 2 moles of CO -482kJ of heat is released for 12.0 g we must find the moles of how much CO is in 12.0g m = 12.0 M = CO = 12.01 + 16 =28.01 g/mol n = 0.428mols so for 2mols -482kJ is released... make a ration 2/482 = 0.428/x x = -103.24 so approx. -103kJ of heat is released