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a) at it's maximum height dy/dx = 0 so -24x+144 = 0 and x = 6 b) when the object hits the ground y = 0 so -12X^2 + 144x + 6 = 0 - solve using quadratic formula c) put y=225 into the equation and solve the quadratic. The difference between the two 'x' values is the time it is above 225 d) set x =...

Efficiency = work got out over work got in = 20J/100J = 0.2 = 20% efficient Energy wasted = energy put in - energy output = 100J - 20J = 80J

a) at it's maximum height dy/dx = 0 so -24x+144 = 0 and x = 6 b) when the object hits the ground y = 0 so -12X^2 + 144x + 6 = 0 - solve using quadratic formula c) put y=225 into the equation and solve the quadratic. The difference between the two 'x' values is the time it is above 225 d) set x =...