Recent content by oldprof

When the turbines are generating, the other sources can cut back on their production of electrical power. When they are not, the other sources have to take up the slack. It's that simple... in concept. Both the turbines and the other, non renewable sources of power, are hooked up to the same...

Doesn't relate at all. Omega is the last letter in the Greek alphabet. So it is the end. Some authors who like to use imagery simply equate the end of the universe to the omega letter as both are the ultimate end. The movie "The Omega Man" was about the last human on Earth; all the others...

False. In classical physics, we'd expect that the relative speed of the tangential speed of Earth rotating into the Sun as the source of light with speed C would be W = C + V. And on the other side, as the spin is away from the Sunny side, we'd expect that W = C - V. But that did not happen...

What if... That's how you extract the most from each example. If you example evoked F = ma to solve for F. Change the problem around. Make up an F and acceleration, and solve for m. Then make up another one that solves for a. Get really imaginative and assume a body of volume V and density...

This is a conservation of energy problem. The start of swing potential energy PE = mgh = 1/2 mV^2 = KE the kinetic energy at the bottom of the swing. Thus V^2 = 2gh and V = sqrt(2gh); where g = 9.81 N/kg, and h = 2.5 m in your case. Note m = 5 kg has no bearing on the problem; meaning V will...

The units would be nice, but are not necessary as we will work this by ratios. KE = 1/2 mV^2 = 1/2 Mv^2 = ke; where m = 3.9E-2 mass units and M = .140 mass units. m/M = (v/V)^2 and v/V = sqrt(m/M) mV = P and Mv = p, the respective momenta. 1) mV V = P V = p v = Mv v from the KE. P/p = v/V...