Find the equation of the normal to the curve; 2x^3 - x(^2)y + y^3 = 1
at the point (2, -3)
So I used implicit differentiation to get the gradient of the tangent.
2x^3 - x(^2)y + y^3 = 1
dy/dx = (2xy - 6x^2) / (3y^2 - x^2) at (2,-3)
= -36 / 23 = Gradient = m
Now I use y - y1 = m(x -x1) to...
A Helium-neon laser (? = 632.8 nm) is used to calibrate a diffraction grating. If the first-order maximum occurs at 20.5 Degrees, what is the line spacing?
Note that ? = lambda