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68ft of a perennial border forms the hypotenuse of the triangle, and one leg is 28ft longer than the other legs. Find the length of the legs. I set it up like this c^2=a^2+b^2 68^2=a^2+(x+28)^2 4624=2x^2+56x+784 0=2^2+56x-3840 0=(x-32)(x+60) x=32 x=-60 what did I do wrong?