Recent content by cattbarf

First, the applicable rxn: Na2CO3 + 2HCl -> CO2 + 2NaCl + H2O This tells us that the mole ratio of sodium carbonate to HCl is 1:1. Given the mass of the sodium carbonate and its mole wt (106), The reactant was present at 265 mg/106g/mole or about 2.5 millimole. So one-tenth of this, or...

Being male, I can do without your undying love. The hangup I see is that 02.mole/dm^3 is the same as 0.1 molar. So you can compute the moles of HCl as 0.2 x 24.3 x 10^-3 = 0.0486 moles. Now, a 1/10th sample would have 0.301 grams of hydrated Na2CO3. BUT whatever the number of waters in...

Being male, I can do without your undying love. The hangup I see is that 02.mole/dm^3 is the same as 0.1 molar. So you can compute the moles of HCl as 0.2 x 24.3 x 10^-3 = 0.0486 moles. Now, a 1/10th sample would have 0.301 grams of hydrated Na2CO3. BUT whatever the number of waters in...

Being male, I can do without your undying love. The hangup I see is that 02.mole/dm^3 is the same as 0.1 molar. So you can compute the moles of HCl as 0.2 x 24.3 x 10^-3 = 0.0486 moles. Now, a 1/10th sample would have 0.301 grams of hydrated Na2CO3. BUT whatever the number of waters in...

1. multiply each atomic mass by its percent occurrence. 2. add the products from above together 3. divide by 100.

First you have to convert to moles. For KOH, appx 4.6/57 moles or 0.081 moles. Assuming the volume of solution is unchanged, its molarity is 0.081 moles/0.25 L = 0.323M. The heat genereated is m * Cp * delta T. m = 255 g, Cp is assumed that of water, 4.18 joule/gram -deg C. delta T =...