Recent content by θ βяιαη θ

It seems that you know how to do this. Basically, choose starting points and iterate until the method converges towards a zero. For the first 3, you are correct. Although, I think they wanted you to write: x_n+1 = x_n - [e^(x_n) + 2(x_n)^2 - 2]/[e^(x_n) + 4(x_n)] For the first one. d) We...

Recall that: -20i = 20(cos 3π/2 + i sin 3π/2) Then, by De Movire's Theorem: (-20i)^(1/4) = 20^(1/4) * [cos (3π/2 + 2πk)/4 + i sin (3π/2 + 2πk)/4] ==> (-20i)^(1/4) = 20^(1/4) * [cos (3π + 4πk)/8 + i sin (3π + 4πk)/8] For k = 0, 1, 2, and 3. For k = 0: (-20i)^(1/4) = 20^(1/4) * (cos 3π/8 + i...